Sounds a lot like what Joel Spolsky was advocating for since 2003, although now it’s easier since most people already have a private office, just not in “the office”.

I’m guessing we need some laws pretty quick to stop this being used in police interviews?

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When you’re 90% through a ASOIAF ebook and it finishes b/c the rest is a list of family names

Even down to them having a stack of records in a room full of more modern technology.

are the negative numbers all even?

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DansData, 2002, has your results: http://dansdata.com/goop.htm

optimised in most of an evening, runs in 0.06 seconds - well at least it will be quick for all of the (one) times that I have to run it!

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progamming ↑↱ excel

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This was interesting! So iterating through the solution space would be infeasible here and it seems we need to look for boundaries between regions and follow them to find places where a solution could occur.

Python: https://pastebin.com/8Ckx36fu

• Make a list of places where location mappings are discontinuous (0, the end of each mapping, and the number before)
• Repeat this for discontinuities in each intermediate layer
• Trace each such location to its seed, and filter by seed ranges
• Run the very minimal set of interesting seed numbers (around 2000 seeds) through the existing part1 algorithm

The input prompt was pretty clear in its intention: “Create a municipal law … which prohibits [agency] from charging the owner of the property for the payment of a new water meter when it is stolen”

Writing that up in the relevant style-guide is all that the AI was asked to do.

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import re
numbers = {
    "one" : 1,
    "two" : 2,
    "three" : 3,
    "four" : 4,
    "five" : 5,
    "six" : 6,
    "seven" : 7,
    "eight" : 8,
    "nine" : 9
    }
for digit in range(10):
    numbers[str(digit)] = digit
pattern = "(%s)" % "|".join(numbers.keys())
   
re1 = re.compile(".*?" + pattern)
re2 = re.compile(".*" + pattern)
total = 0
for line in open("input.txt"):
    m1 = re1.match(line)
    m2 = re2.match(line)
    num = (numbers[m1.group(1)] * 10) + numbers[m2.group(1)]
    total += num
print(total)

There weren’t any zeros in the training data I got - the text seems to suggest that “0” is allowed but “zero” isn’t.

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Newspaper: Hackers are announcing a trove of personal data leaked from [company] after a forwarded spreadsheet inadvertently contained more data than the sender realised.