Day 2: Cube Conundrum


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FAQ


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  • Cyno@programming.dev
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    7 months ago

    Was pretty simple in Python with a regex to get the game number, and then the count of color. for part 2 instead of returning true/false whether the game is valid, you just max the count per color. No traps like in the first one, that I’ve seen, so it was surprisingly easy

    def process_game(line: str):
        game_id = int(re.findall(r'game (\d+)*', line)[0])
    
        colon_idx = line.index(":")
        draws = line[colon_idx+1:].split(";")
        # print(draws)
        
        if is_game_valid(draws):
            # print("Game %d is possible"%game_id)
            return game_id
        return 0
    
                
    def is_game_valid(draws: list):
        for draw in draws:
            red = get_nr_of_in_draw(draw, 'red')
            if red > MAX_RED:
                return False
            
            green = get_nr_of_in_draw(draw, 'green')
            if green > MAX_GREEN:
                return False
            
            blue = get_nr_of_in_draw(draw, 'blue')
            if blue > MAX_BLUE:
                return False    
        return True
            
                
    def get_nr_of_in_draw(draw: str, color: str):
        if color in draw:
            nr = re.findall(r'(\d+) '+color, draw)
            return int(nr[0])
        return 0
    
    
    # f = open("input.txt", "r")
    f = open("input_real.txt", "r")
    lines = f.readlines()
    sum = 0
    for line in lines:
        sum += process_game(line.strip().lower())
    print("Answer: %d"%sum)